RSA is easy

Author: stackola

• challenge_files.zip

Explanation

Textbook RSA; each char of flag encrypted individually, no padding used, so just use the pk to create a map of enc(pk,x) -> x for all ASCII chars and then read out the flag by querying the map for each encrypted char.

flag

HackTM{why_ar3_MY_pR1va7es_pu8l1C_??}